The bottom part is a graph of the equation, which, as you can see, is exactly the same. To be fair, this equation cheats a little bit. You may notice that the y-axis of that graph begins at ‘k’.

The graph below has a turning point (3, -2). Write down the nature of the turning point and the equation of the axis of symmetry. For the parabola \(y=(x+6)(x-4)\) determine the coordinates and ...

The graph of y = x 2 6 x + 9 touches the x -axis at x = 3. The coefficient of x 2 is positive, so the graph will be a positive U-shaped curve.